A) Equal
B) Imaginary
C) Real
D) None of these
Correct Answer: C
Solution :
We have \[4a{{x}^{2}}+3bx+2c=0\] Let roots are \[\alpha \] and \[\beta \] Let \[D={{B}^{2}}-4AC\]\[=\,\,9{{b}^{2}}-4(4a)(2c)=9{{b}^{2}}-32ac\] Given that, \[(a+b+c)=0\Rightarrow b=-(a+c)\] Putting this value, we get \[=9{{(a+c)}^{2}}-32ac=9{{(a-c)}^{2}}+4ac\]. Hence roots are real.You need to login to perform this action.
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