A) Rational
B) Irrational
C) Real
D) Imaginary
Correct Answer: D
Solution :
Given equation \[2({{a}^{2}}+{{b}^{2}}){{x}^{2}}+2(a+b)x+1=0\] Let \[A=2({{a}^{2}}+{{b}^{2}}),B=2(a+b)\]and \[C=1\] \[{{B}^{2}}-4AC=4({{a}^{2}}+{{b}^{2}}+2ab)-4\,.2({{a}^{2}}+{{b}^{2}})\,1\] \[\Rightarrow {{B}^{2}}-4AC=-4{{(a-b)}^{2}}<0\] Thus given equation has imaginary roots.You need to login to perform this action.
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