A) 0.38
B) 0.44
C) 0.52
D) 0.60
Correct Answer: A
Solution :
Coefficient of friction \[{{\mu }_{s}}=\frac{{{F}_{l}}}{R}=\frac{75}{mg}=\frac{75}{20\times 9.8}\]\[=0.38\]You need to login to perform this action.
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