A) 900 N
B) 100 N
C) 1100 N
D) 1200 N
Correct Answer: C
Solution :
\[F={{f}_{AB}}+{{f}_{BG}}\] \[={{\mu }_{AB}}{{m}_{a}}g+{{\mu }_{BG}}({{m}_{A}}+{{m}_{B}})g\] \[=0.2\times 100\times 10\] \[+0.3(300)\times 10\] \[=200+900=1100\ N\]You need to login to perform this action.
You will be redirected in
3 sec