A) \[12x-5y+8=0\], \[12x-5y=252\]
B) \[12x-5y=0,\,\,12x-5y=252\]
C) \[12x-5y-8=0,\,12x-5y+252=0\]
D) None of these
Correct Answer: A
Solution :
Equation of line perpendicular to \[5x+12y+8=0\] is \[12x-5y+k=0\]. Now it is a tangent to the circle, if Radius of circle = Distance of line from centre of circle \[\sqrt{121+4-25}=\left| \frac{12(11)-5(2)+k}{\sqrt{144+25}} \right|\]\[\Rightarrow k=8\] or ? 252. Hence equations of tangents are \[12x-5y+8=0\] and \[12x-5y=252\].You need to login to perform this action.
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