A) 0 or a
B) 0
C) \[2a\]
D) \[0\]or \[2a\]
Correct Answer: D
Solution :
\[x\cos \alpha +y\sin \alpha -p=0\] is a tangent, if perpendicular from centre on it is equal to radius of the circle. Here centre is \[(a\cos \alpha ,\ a\sin \alpha )\] and radius is a. \ \[\left| \frac{a{{\cos }^{2}}\alpha +a{{\sin }^{2}}\alpha -p}{\sqrt{1}} \right|=a\] i.e. \[|a-p|\ =a\Rightarrow p=0\] or \[p=2a\].You need to login to perform this action.
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