JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Topic Test - Chemical Equilibrium (6-5-21)

  • question_answer
    What is the effect of increasing pressure on the dissociation of \[PC{{l}_{5}}\] according to the equation \[PC{{l}_{5(g)}}\]\[\rightleftharpoons \] \[PC{{l}_{3(g)}}+C{{l}_{2(g)}}-x\ cal\]   

    A)       Dissociation decreases

    B) Dissociation increases

    C) Dissociation does not change

    D) None of these

    Correct Answer: A

    Solution :

    [a] \[PC{{l}_{5}}(g)\] \[\rightleftharpoons \]\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
             For this reaction \[\Delta n=2-1=1\]
                Value of \[\Delta n\] is positive so the dissociation of \[PC{{l}_{5}}\] take forward by decrease in pressure & by increase in pressure the dissociation of \[PC{{l}_{5}}\] decrease.

You need to login to perform this action.
You will be redirected in 3 sec spinner