• # question_answer The vapour density of completely dissociated $N{{H}_{4}}Cl$ would be                 A) Slight less than half that of $N{{H}_{4}}Cl$ B) Half  that of $N{{H}_{4}}Cl$ C) Double that of $N{{H}_{4}}Cl$ D) Determined by the amount of solid $N{{H}_{4}}Cl$ in the experiment

Correct Answer: B

Solution :

 [b] $\frac{\text{Normal}\,\,\text{molecular}\,\,\text{weight}}{\text{experimental}\,\,\text{molecular}\,\,\text{wt}\text{.}}$= 1 + a $N{{H}_{4}}Cl$ $\rightleftharpoons$ $N{{H}_{3}}+HCl$ $\because \alpha =1$ \Experimental Molecular wt =$\frac{\text{nor}\text{.mol}\text{.wt}\text{.}}{2}$

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