A) 5472 kJ/mol
B) 48 kJ/mol
C) 684 kJ/mol
D) 4281 kJ/mol
Correct Answer: A
Solution :
[a] Rise in temperature = 300 - 294 = 6 K |
Heat given to the calorimeter |
= Heat capacity \[\times \,\Delta T\]\[=8\times 6\] |
= 48 kJ |
Molar mass of octane \[({{C}_{8}}{{H}_{18}})=114\] |
1 g of octane gives = 48 kJ heat |
114 g of octane = 1 mol of octane gives |
\[=48\times 114\,\,kJ\] |
= 5472 kJ/mol |
You need to login to perform this action.
You will be redirected in
3 sec