A) - 132 kJ
B) - 72 kJ
C) + 80 kJ
D) + 162 kJ
Correct Answer: B
Solution :
[b] \[n(C{{H}_{2}}=C{{H}_{2}})\xrightarrow{\ }\,{{(-C{{H}_{2}}-C{{H}_{2}}-)}_{n}},\] |
\[\Delta H=?\] |
Thus, 'n' double bonds are dissociated to form a molecule with 2n single bonds. |
\[\Delta H=\left( \frac{n}{n} \right)({{\Sigma }_{C=C}})-\left( \frac{2n}{n} \right)({{\Sigma }_{C=C}})\] |
\[=+\,590-2\times 331=-72\,kJ\,mo{{l}^{-1}}\] |
You need to login to perform this action.
You will be redirected in
3 sec