• # question_answer A gas for which $\gamma =1.5$is suddenly compressed to$\frac{1}{4}$th of the initial volume. Then the ratio of the final to the initial pressure is        A) 1 : 16 B) 1 : 8 C) 1 : 4 D) 8 : 1

[d] ${{P}_{1}}V_{1}^{\gamma }={{P}_{2}}V_{2}^{\gamma }$Þ $\frac{{{P}_{2}}}{{{P}_{1}}}={{\left[ \frac{{{V}_{1}}}{{{V}_{2}}} \right]}^{\gamma }}={{\left[ \frac{4}{1} \right]}^{3/2}}=\frac{8}{1}$