A) 1 : 16
B) 1 : 8
C) 1 : 4
D) 8 : 1
Correct Answer: D
Solution :
[d] \[{{P}_{1}}V_{1}^{\gamma }={{P}_{2}}V_{2}^{\gamma }\]Þ \[\frac{{{P}_{2}}}{{{P}_{1}}}={{\left[ \frac{{{V}_{1}}}{{{V}_{2}}} \right]}^{\gamma }}={{\left[ \frac{4}{1} \right]}^{3/2}}=\frac{8}{1}\]
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