A) Zero
B) \[P({{V}_{2}}-{{V}_{1}})\]
C) \[L-P({{V}_{2}}-{{V}_{1}})\]
D) L
Correct Answer: C
Solution :
[c] \[\Delta Q=\Delta V+P\Delta V\]Þ mL = DU + P(V2 V1) |
Þ DU = L P (V2 V1) (\[\because \] m = 1) |
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