A) \[{{30}^{o}}\]
B) \[{{60}^{o}}\]
C) \[{{45}^{o}}\]
D) \[{{75}^{o}}\]
Correct Answer: B
Solution :
Given, \[\cos P=\frac{1}{7},\cos Q=\frac{13}{14}\] \\[\cos (P-Q)=\cos P\cos Q+\sin P\sin Q\] \[=\frac{1}{7}.\frac{13}{14}+\frac{\sqrt{48}}{7}.\frac{\sqrt{27}}{14}=\frac{13+36}{98}=\frac{1}{2}=\cos {{60}^{o}}\] Þ \[P-Q={{60}^{o}}\].
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