A) \[1\]
B) \[\frac{1}{2}\]
C) \[\frac{1}{4}\]
D) \[\frac{3}{4}\]
Correct Answer: B
Solution :
[b] \[\therefore \]\[\sin \theta -\cos \theta =0\]\[\Rightarrow \]\[\tan \theta =1\] \[\Rightarrow \] \[\theta =45{}^\circ \] \[\therefore \]\[(si{{n}^{4}}\theta +co{{s}^{4}}\theta )\] \[={{\left( \frac{1}{\sqrt{2}} \right)}^{4}}+{{\left( \frac{1}{\sqrt{2}} \right)}^{4}}\] =\[\left( \frac{1}{4}+\frac{1}{4} \right)=\frac{2}{4}=\frac{1}{2}\] |
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