A) \[15{}^\circ \]
B) \[30{}^\circ \]
C) \[45{}^\circ \]
D) \[60{}^\circ \]
Correct Answer: C
Solution :
[c] \[\tan \,(A+B)=\sqrt{3}=\tan 60{}^\circ \] \[\Rightarrow \] \[A+B=60{}^\circ \] and \[\tan \,(A-B)=\frac{1}{\sqrt{3}}=\tan \text{ }30{}^\circ \] \[\Rightarrow \] \[A-B=30{}^\circ \] (ii) On adding Eqs. (i) and (ii), we get \[2A=90{}^\circ \] \[\Rightarrow \] \[A=45{}^\circ \] |
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