A) ? 2.86 V
B) ? 4 V
C) + 4 V
D) + 2 V
Correct Answer: A
Solution :
By using \[\mu =-\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}\]\[={{r}_{p}}\times {{g}_{m}}\] \[\Rightarrow 7\times {{10}^{3}}\times 2.5\times {{10}^{-3}}=-\frac{50}{\Delta {{V}_{g}}}\]\[\Rightarrow \Delta {{V}_{g}}=-2.86\,V\].
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