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JEE Main & Advanced Physics Semiconducting Devices Question Bank Valve Electronics (Diode and Triode)

  • question_answer
    The amplification factor of a triode is 20 and trans-conductance is 3 milli mho and load resistance \[3\times {{10}^{4}}\Omega \], then the voltage gain is                                                      [RPMT 1996]

    A)            16.36                                       

    B)            28

    C)            78  

    D)            108

    Correct Answer: A

    Solution :

                       Using voltage gain \[{{A}_{v}}=\frac{\mu }{1+\frac{{{r}_{p}}}{{{R}_{L}}}}\] also \[\mu ={{r}_{p}}\times {{g}_{m}}\]                    \[\Rightarrow {{r}_{p}}=\frac{\mu }{{{g}_{m}}}=\frac{20}{3\times {{10}^{-3}}}\]                    \[\therefore {{A}_{v}}=\frac{20}{1+\frac{20}{3\times {{10}^{-3}}\times 3\times {{10}^{4}}}}\]=\[\frac{180}{11}\]=16.36.


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