A) \[y=\frac{a{{e}^{x}}}{b}+\frac{c}{m}\sin mx+k\]
B) \[y=a{{e}^{x}}+c\sin mx+k\]
C) \[y=\frac{a{{e}^{bx}}}{b}+\frac{c}{m}\sin mx+k\]
D) None of these
Correct Answer: C
Solution :
\[\frac{dy}{dx}=(a{{e}^{bx}}+c\cos mx)\] Þ \[dy=(a{{e}^{bx}}+c\cos mx)dx\] On integrating, \[y=\frac{a{{e}^{bx}}}{b}+\frac{c\sin (mx)}{m}+k\].You need to login to perform this action.
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