A) \[y=2\tan \frac{x}{2}-x+c\]
B) \[y=2\tan x+x+c\]
C) \[y=2\tan \frac{x}{2}+x+c\]
D) \[y=x-2\tan \frac{x}{2}+c\]
Correct Answer: A
Solution :
Here \[\frac{dy}{dx}=\frac{1-\cos x}{1+\cos x}={{\tan }^{2}}\frac{x}{2}\] Þ \[dy=\left( {{\sec }^{2}}\frac{x}{2}-1 \right)\,dx\] Now on integrating both the sides, we get \[y=2\tan \frac{x}{2}-x+c\].You need to login to perform this action.
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