A) \[\frac{2x-1}{2y+3}=c\]
B) \[\frac{2y+1}{2x-3}=c\]
C) \[\frac{2x+3}{2y-1}=c\]
D) s \[\frac{2x-1}{2y-1}=c\]
Correct Answer: C
Solution :
\[\frac{dy}{2y-1}=\frac{dx}{2x+3}\] Þ \[\frac{1}{2}\log (2y-1)=\frac{1}{2}\log (2x+3)+\log c\] Þ \[\frac{2x+3}{2y-1}=c\].You need to login to perform this action.
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