A) \[y=\cos x\]
B) \[x=c\sec y\]
C) \[x=\sin y\]
D) \[y=\sin x\]
Correct Answer: B
Solution :
\[\cot y.dx=x.dy\] Þ \[\frac{dx}{x}=\frac{dy}{\cot y}\] Þ \[\frac{dx}{x}=\tan y.dy\] Integrating both sides, \[\log x=\log \sec y+\log c\] Þ \[x=c\sec y\].You need to login to perform this action.
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