A) 5, 10
B) 3, 2
C) 4, 2
D) 3, 4
Correct Answer: A
Solution :
\[x=3\sin 2t+4\cos 2t.\]From given equation \[{{a}_{1}}=3,\ {{a}_{2}}=4,\] and \[\varphi =\frac{\pi }{2}\] \\[a=\sqrt{a_{1}^{2}+a_{2}^{2}}\]\[=\sqrt{{{3}^{2}}+{{4}^{2}}}=5\]Þ\[{{v}_{\max }}=a\omega =5\times 2=10\]You need to login to perform this action.
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