A) 4v
B) 2v
C) \[\frac{\sqrt{3}}{2}v\]
D) \[\frac{\sqrt{3}}{4}v\]
Correct Answer: C
Solution :
Velocity in mean position \[v=a\omega ,\] velocity at a distance of half amplitude. \[{v}'=\omega \sqrt{{{a}^{2}}-{{y}^{2}}}\]\[=\omega \sqrt{{{a}^{2}}-\frac{{{a}^{2}}}{4}}\]\[=\sqrt{\frac{3}{2}}\,a\omega =\sqrt{\frac{3}{2}}\,v\]You need to login to perform this action.
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