JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Variable Force

  • question_answer
    A mass of 0.5kg moving with a speed of 1.5 m/s on a horizontal smooth surface, collides with a nearly weightless spring of force constant \[k=50\ N/m\]. The maximum compression of the spring would be  [CBSE PMT 2004]

    A)             0.15 m

    B)               0.12 m

    C)             1.5 m  

    D)             0.5 m

    Correct Answer: A

    Solution :

                    The kinetic energy of mass is converted into potential energy of  a spring             \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}\]Þ \[x=\sqrt{\frac{m{{v}^{2}}}{k}}=\sqrt{\frac{0.5\times {{(1.5)}^{2}}}{50}}=0.15\,m\]

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