A) \[{{10}^{-5}}\]J
B) \[2.5\times {{10}^{-5}}\]J
C) \[5\times {{10}^{-5}}\]J
D) \[2.5\times {{10}^{-4}}\]J
Correct Answer: B
Solution :
\[U=\frac{1}{2}\times \frac{{{\text{(stress)}}^{\text{2}}}}{Y}\times \text{volume}\]= \[\frac{1}{2}\times \frac{{{F}^{2}}\times A\times L}{{{A}^{2}}\times Y}\] =\[\frac{1}{2}\times \frac{{{F}^{2}}L}{AY}=\frac{1}{2}\times \frac{{{(50)}^{2}}\times 0.2}{1\times {{10}^{-4}}\times 1\times {{10}^{11}}}\]= \[2.5\times {{10}^{-5}}J\]You need to login to perform this action.
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