A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) 1
Correct Answer: C
Solution :
Work done in stretching a wire \[W=\frac{1}{2}Fl=\frac{1}{2}\times 10\times 0.5\times {{10}^{-3}}\]= \[2.5\times {{10}^{-3}}J\] Work done to displace it through 1.5 mm \[W=F\times l=5\times {{10}^{-3}}J\] The ratio of above two work = 1 : 2You need to login to perform this action.
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