JEE Main & Advanced
Physics
Elasticity
Question Bank
Work Done in Stretching a Wire
question_answer
A wire is suspended by one end. At the other end a weight equivalent to 20 N force is applied. If the increase in length is 1.0 mm, the increase in energy of the wire will be
A)0.01 J
B) 0.02 J
C) 0.04 J
D) 1.00 J
Correct Answer:
A
Solution :
Increase in energy \[=\frac{1}{2}\times 20\times 1\times {{10}^{-3}}=0.01J\]