Answer:
Given, \[m=2\,\,kgu=20\,m/s\] \[t=2\,sg=10\,m/{{s}^{2}}\] \[P.E.=?\] We know, \[P.E.=mgh\] First we have to find ?h?. From the relation, \[S=ut+\frac{1}{2}g{{t}^{2}}\] We get, \[h=20\times 2-\frac{1}{2}\times 10\times {{(2)}^{2}}\] \[=40-20=20\,m\] \[\therefore \,\,P.E.=2\times 10\times 20=400\,J\]
You need to login to perform this action.
You will be redirected in
3 sec