Answer:
Given, \[m=50\,\,kgh=100\,m\] \[W=?P.E.=?\] We know, Work done against gravity \[(W)=mgh\] \[W=50\times 9.8\times 100=49000\,J\] We also know that, \[P.E.=mgh\] \[P.E.=50\times 9.8\times 100=49000\,J\] \[\therefore \]the boy gains 49000 J of potential energy.
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