A) \[\frac{13}{24}\]
B) \[\frac{11}{30}\]
C) \[\frac{13}{32}\]
D) \[\frac{13}{36}\]
Correct Answer: D
Solution :
\[\frac{1}{{{x}^{2}}}+\frac{1}{{{y}^{2}}}=\frac{{{x}^{2}}+{{y}^{2}}}{{{x}^{2}}{{y}^{2}}}=\frac{{{(x+y)}^{2}}-2xy}{{{(xy)}^{2}}}\] \[=\frac{{{(5)}^{2}}-2(6)}{{{(6)}^{2}}}=\frac{25-12}{36}=\frac{13}{36}\]You need to login to perform this action.
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