A) 3
B) - 8
C) 14
D) ? 4
Correct Answer: A
Solution :
Let \[f(x)={{x}^{3}}-3{{x}^{2}}+4x-15\] Let m to be added, then \[\therefore \] \[g(x)\times f(x)+m\] \[\Rightarrow \] \[g(x)={{x}^{3}}-3{{x}^{2}}+4x-15+m\] \[\Rightarrow \] \[g(3)=0\] \[\Rightarrow \] \[g(3)={{(3)}^{3}}-3\times {{(3)}^{2}}+4(3)-15+m=0\] \[\Rightarrow \] \[m-3=0\] \[\therefore \] \[m=3\]You need to login to perform this action.
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