Directions (Q. 17-20): Study the table and answer the given questions: The table depicts graduates in 5 towns in 2015.
Town | % of graduates in total population (male + female) | % of graduates in male population | % of graduates in female population |
V | ? | 75 | 70 |
W | 60 | 65 | 55 |
X | 72.5 | 73 | 62 |
Y | 58 | ? | 60 |
Z | 60 | ? | 60 |
A) 1872
B) 2850
C) 2150
D) 3250
E) 3100
Correct Answer: E
Solution :
Total number of graduate population in Town \[Z=4200\] \[\therefore \]Total population \[=100\times \frac{4200}{60}=7000\] \[\therefore \]Total non-graduate population\[=7000-4200\]\[=2800\] Let the no. of non-graduate males be\[x\]. Now, according to the question, Non-graduate females\[=x+320\] \[\therefore \]\[x+x+320=2800\] or,\[2x=2800-320\] or,\[x=\frac{2480}{2}=1240\] \[\therefore \]Non-graduate males\[=1240\] Non-graduate female \[=1240+520=1560\] % of non-graduate females \[=100-60=40%\] \[\therefore \]\[40%=1560\] \[\therefore \]\[100%=3900\] \[\therefore \]Total male population\[=7000-3900=3100\]You need to login to perform this action.
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