Directions (Q. 17-20): Study the table and answer the given questions: The table depicts graduates in 5 towns in 2015.
Town | % of graduates in total population (male + female) | % of graduates in male population | % of graduates in female population |
V | ? | 75 | 70 |
W | 60 | 65 | 55 |
X | 72.5 | 73 | 62 |
Y | 58 | ? | 60 |
Z | 60 | ? | 60 |
A) 67%
B) 23%
C) 47%
D) 56%
E) 35%
Correct Answer: D
Solution :
Let the male population in Town W in 2015 be\[x\]. Then No. of male population in Town W in\[2016=x\times \frac{115}{100}=\frac{23x}{20}\] Now, graduate males in 2015 = Graduate males in 2016 Let \[y%\] males be graduate in 2016. Then,\[x\times \frac{65}{100}=\frac{23x}{20}\times \frac{y}{100}\] \[\therefore \]\[y\approx 56%\]You need to login to perform this action.
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