A) \[5.5\times {{60}^{-12}}J\]
B) \[1.1\times {{10}^{-11}}J\]
C) \[2.2\times {{10}^{-11}}J\]
D) \[1.65\times {{10}^{-11}}J\]
Correct Answer: B
Solution :
[b]: Energy contained in a cylinder U = average energy density\[\times \]volume \[=\frac{1}{2}{{\varepsilon }_{0}}E_{0}^{2}\times Al\] \[=\frac{1}{2}\times (8.85\times {{10}^{-12}})\times {{(50)}^{2}}\times (10\times {{10}^{-4}})\times 1\] \[=1.1\times {{10}^{-11}}J\]You need to login to perform this action.
You will be redirected in
3 sec