A) \[1/(10\lambda )\]
B) \[1/(8\lambda )\]
C) \[11/(10\lambda )\]
D) \[1/(9\lambda )\]
Correct Answer: B
Solution :
[b] \[{{N}_{1}}={{N}_{0}}{{e}^{-10\lambda t}}\] and \[{{N}_{2}}={{N}_{0}}{{e}^{-2\lambda t}}\] \[\Rightarrow \,\,\,\frac{{{N}_{1}}}{{{N}_{2}}}=\frac{1}{e}={{e}^{-1}}={{e}^{(-10\lambda +2\lambda )\,t}}={{e}^{-8\lambda t}}\] \[\Rightarrow \,\,\,\,\,\,\,t=\frac{1}{8\lambda }\]You need to login to perform this action.
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