A) If \[{{V}_{B}}=12\] volt, the power dissipated in Zener diode will exceed the maximum power limit, specified for it.
B) If \[{{V}_{B}}=12\] volt, the power dissipated in Zener diode will not exceed the maximum power limit, specified for it.
C) If \[{{V}_{B}}=15\]volt, the power dissipated in Zener diode will exceed the maximum power limit, specified for it.
D) If \[{{V}_{B}}=20\]volt, the power dissipated in Zener diode will not exceed the maximum power limit, specified for it.
Correct Answer: B
Solution :
[b] \[1000I+1000(I-{{I}_{Z}})={{V}_{B}}\] \[\Rightarrow \,\,\,\,\,2I-{{I}_{Z}}={{V}_{B}}\times {{10}^{-3}}\] ...(i) |
\[-500{{I}_{z}}-{{V}_{z}}+1000(I-{{I}_{Z}})=0\] \[-1500{{I}_{z}}+1000\,I={{V}_{z}}\] \[=1.5{{I}_{z}}+I={{V}_{z}}\times {{10}^{-3}}\] \[=1.5{{I}_{z}}+I=3\times {{10}^{-3}}\] \[2I-3{{I}_{z}}=6\times {{01}^{-3}}\] ? (ii) With equations (i) and (ii), we have \[2{{I}_{z}}=\left( {{V}_{B}}-6 \right)\times {{10}^{-3}}\] \[\Rightarrow \,\,{{I}_{Z}}=\frac{{{V}_{B}}-6}{2}mA\] \[{{P}_{Z}}={{V}_{Z}}{{I}_{Z}}=\frac{3{{V}_{B}}-18}{2}\le 18\,\,\,\,\,\Rightarrow \,\,\,\,\,\,\,{{V}_{B}}\le 18\] Volt |
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