A) \[\frac{2Mgd}{\pi {{R}^{2}}{{B}_{0}}}\]
B) \[\frac{2\pi Mgd}{{{R}^{2}}{{B}_{0}}}\]
C) \[\frac{Mgd}{2\pi {{R}^{2}}{{B}_{0}}}\]
D) \[\frac{\pi Mgd}{2{{R}^{2}}{{B}_{0}}}\]
Correct Answer: C
Solution :
[c] Magnetic dipole moment of loop is \[\mu =I\pi {{R}^{2}}\] (direction as shown). Magnetic torque on the loop is \[\tau =\mu {{B}_{0}}\sin 90{}^\circ =I\pi {{R}^{2}}{{B}_{0}}\] (in the direction shown)You need to login to perform this action.
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