A) zero
B) \[\frac{q}{4\pi {{\varepsilon }_{0}}\sqrt{2}R}\left( {{Q}_{1}}-{{Q}_{2}} \right)\left( \sqrt{2}-1 \right)\]
C) \[\frac{q\sqrt{2}}{4\pi {{\varepsilon }_{0}}R}\left( {{Q}_{1}}+{{Q}_{2}} \right)\]
D) \[\frac{\left( \sqrt{2}-1 \right)\,q\left( {{Q}_{1}}+{{Q}_{2}} \right)}{\sqrt{2}4\pi {{\varepsilon }_{0}}R}\]
Correct Answer: B
Solution :
[b] Work \[=q\,({{V}_{A}}-{{V}_{B}})\] \[=\frac{q\,\left( {{Q}_{1}}-{{Q}_{2}} \right)\,\left( \sqrt{2}-1 \right)}{4\pi {{\varepsilon }_{0}}\sqrt{2}R.}\] (\[\because \] potential at A = potential due to \[{{Q}_{1}}+\]potential due to \[{{Q}_{2}}\])You need to login to perform this action.
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