• # question_answer If $n\in N$, then ${{11}^{n+2}}+{{12}^{2n+1}}$ is divisible by A) 113        B) 123 C) 133                   D) None of these

[c] : On putting n= 1 in ${{11}^{n+2}}+{{12}^{2n+1}},$we get ${{11}^{n+2}}+{{12}^{(2\times 1)+1}}={{11}^{3}}+{{12}^{3}}=3059$which is divisible by 133 only.