A) 16/15
B) 15/16
C) 31/16
D) none of these
Correct Answer: D
Solution :
[d]: We have, \[f(x)=\frac{k}{{{2}^{x}}}\]. Clearly, \[f(0)+f(1)+...+f(4)=1\] \[\Rightarrow \]\[k+\frac{k}{2}+.....+\frac{k}{{{2}^{4}}}=1\]\[\Rightarrow \]\[\frac{k[1-{{(1/2)}^{5}}]}{1-1/2}=1\] \[\Rightarrow \]\[\frac{k(31/32)}{1/2}=1\Rightarrow k=\frac{16}{31}\]You need to login to perform this action.
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