A) 2
B) -2
C) 1
D) -1
Correct Answer: A
Solution :
[a] : Given, equation of curve is \[y=1+bx-{{x}^{2}}\]\[\Rightarrow \]\[\frac{dy}{dx}=b-2x.\]\[\Rightarrow \]\[{{\left. \frac{dy}{dx} \right|}_{(1,-2)}}=b-2\] Since, tangent at (1, -2) is parallel to x-axis \[\therefore \]\[{{\left. \frac{dy}{dx} \right|}_{(1,-2)}}=0\Rightarrow b-2=0\Rightarrow b=2\].You need to login to perform this action.
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