A) a, b, c are ail real
B) at least one of a, b, c is real
C) at least one of a. b, c is imaginary
D) a, b. c are all imaginary.
Correct Answer: C
Solution :
\[a{{z}^{2}}+bz+c=0\]\[lm({{z}_{1}}{{z}_{2}})\ne 0\Rightarrow \]roots cannot be complex conjugate of each other \[\therefore \]all a,b,c cannot be real hence, at least one of them is imaginary.You need to login to perform this action.
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