A) 0
B) 1
C) 2
D) 3 [Note: Tr. (P) denotes trace of matrix P.J
Correct Answer: D
Solution :
\[tr(A)={{x}^{2}}+{{y}^{2}}+{{z}^{2}}\] \[tr(B)=2x+2y+2z-3\] \[{{(x-1)}^{2}}+{{(y-1)}^{2}}+{{(z-1)}^{2}}=0\] \[\therefore \]\[x=y=z=1\]Hence,\[(x+y+z)=3\].You need to login to perform this action.
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