A) \[\frac{20}{3}\,\mu C\]
B) \[\frac{10}{3}\,\mu C\]
C) \[\frac{5}{6}\,\mu C\]
D) \[10\,\mu C\]
Correct Answer: A
Solution :
In the steady state, the capacitors are fully charged and act as an open circuit, so the equivalent circuit in steady state would be as shown in figure. Steady state current,\[I=\frac{10}{5+5}=1A\] So, potential drop across AB, \[V=5\text{ }V\] Sum of potential difference across \[2\mu F\]and \[4\mu F\] capacitors is 5 V. As capacitors are in series, charges on them would be the same. Let us say it is q. From KVL \[\frac{q}{2}+\frac{f}{4}=5\] \[\Rightarrow \] \[q=\frac{20}{3}\mu C\]You need to login to perform this action.
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