A) 5
B) 3
C) 7
D) 1
Correct Answer: A
Solution :
In YDSE, path difference,\[\Delta x=d\sin \theta \] For maxima, \[\Delta x=n\lambda \]where \[n=0,\pm 1,\pm \,2,...\] \[\Rightarrow \] \[\frac{5\lambda }{2}\sin \theta =n\lambda \] Since \[\sin \theta <1,\] \[\frac{2n}{5}\le 1\] \[\Rightarrow \] \[n\le \frac{5}{2}\] i.e., \[n\] can have values \[0,\pm \,1,\pm \,\,2.\] So, a total of 5 maxima can be obtained.You need to login to perform this action.
You will be redirected in
3 sec