A) \[2\sqrt{2}\]
B) \[4\sqrt{2}\]
C) \[\sqrt{2}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: B
Solution :
According the Graham's law of diffusion \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{D}_{2}}}}}}\] \[\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}=\frac{\frac{8}{4}}{\frac{32}{32}}=2\] \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{D}_{2}}}}}}=2\times \sqrt{\frac{32}{4}}\] \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=2\times \sqrt{8}=4\sqrt{2}\]You need to login to perform this action.
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