A) \[1-\frac{5{{K}_{c}}}{{{V}^{5}}}\]
B) \[\frac{5{{K}_{c}}}{{{V}^{5}}}\]
C) \[1-\frac{5K_{c}^{2}}{{{V}^{5}}}\]
D) \[1-\frac{4K_{c}^{2}}{{{V}^{4}}}\]
Correct Answer: A
Solution :
\[\frac{PV}{RT}=\]Total no. of moles of gases at equilibrium.You need to login to perform this action.
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