A) 3
B) 4
C) 2
D) 1
Correct Answer: C
Solution :
Number of moles \[HCl=\frac{0.192}{36.5}=0.0053\] Volume = 0.5 L conc. of \[\text{HCl}=\frac{0.0053}{0.5}=1.06\times {{10}^{-2}}M\] \[[{{H}^{+}}]\] in \[HCl\] solution \[=1.06\times {{10}^{-2}}\times \frac{95}{100}\] \[=100.7\times {{10}^{-4}}=1\times {{10}^{-2}}\] \[pH=-\log \,[{{H}^{+}}]=2\]You need to login to perform this action.
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