A) 2
B) 3.3
C) 4.0
D) 4.5
Correct Answer: B
Solution :
When \[pH=5,\,\,[{{H}^{+}}]={{10}^{-5}}M\] When \[pH=3,\,[{{H}^{+}}]={{10}^{-3}}M\] Total \[[{{H}^{+}}]=\frac{{{10}^{-5}}+{{10}^{-3}}}{2}\] \[=\frac{{{10}^{-3}}(1+0.01)}{2}=0.50\times {{10}^{-3}}\] \[pH=-\log \,[{{H}^{+}}]=-\log \,(0.50\times {{10}^{-3}})=3.3\]You need to login to perform this action.
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