A) 15m
B) 25m
C) 20m
D) 30m
Correct Answer: B
Solution :
\[t=\frac{v}{g}=\frac{20}{10}=2\sec \] \[h=\frac{1}{2}g{{t}^{2}}=\frac{1}{2}\times 10\times {{1}^{2}}=5\] \[h=\frac{{{v}^{2}}}{2g}=20\] distance = path length = 20 + 5 = 25mYou need to login to perform this action.
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